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Given the that the radial wavelength of the atomic probability density of an electron in a hydrogen atom is given as P(r)dr = R*(r)R(r)4(Pi)2dr, where R(r) given as the radial component of the solution of the atomic Schrodinger equation Psi(r,Theta,Phi) = (Zr/a)l*Gnl*(Zr/a)*eZr/na*sin|ml|(Theta x Fl,ml)*cos(Theta)*ei*m*Phi where m,l,n are integers that follow the relationship n = 1,2,3,...; l = 1,2,3,..., n - 2, n - 1; m = -l, -l + 1, -l + 2 ... l - 2, l - 1, l. Does the probability density of the electron have axial symmetry when m != 0?